Egyptian forward Mohamed Salah on Tuesday at a colourful ceremony held in Dakar, Senegal, won the 2018 CAF Player of the Year award.
Salah, 26, beat Liverpool team-mate Sadio Mane of Senegal and Arsenal and Gabon striker Pierre-Emerick Aubameyang to the title.
He received the award at a ceremony in Senegal on Tuesday.
With the Liverpool striker keeping the award in 2018, he has joined the list of the few players who won two awards in a row such as El-Hadji Diouf from Senegal (2001, 2002), Samuel Eto’o from Cameroon (2003, 2004) and Yaya Toure from Ivory Coast (2011, 2012)
“I have dreamt of winning this award since I was a child and now I have done so twice in a row, ” Salah said.
The former Napoli striker scored 44 goals for Liverpool during the 2017-18 season, helping the Reds to the Champions League final before scoring twice for Egypt at the World Cup in Russia.
He has scored 16 goals in 29 appearances across all competitions for Liverpool this season.
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Mohamed Salah is the African Player of the Year 2018. For the second time in a row #AiteoCAFAwards18 pic.twitter.com/iLKIFDnZqB
— CAF (@CAF_Online) January 8, 2019
Happy to be part of the Africa best XI 2018 ???? https://t.co/m6iYssym3F
— Koulibaly Kalidou (@kkoulibaly26) January 8, 2019